Practice
practice problem 1
Write something else.
solution
practice problem 2
A bucket grain elevator is powered by a 150 kW electric motor. Determine its efficiency if it can lift grain to a height of 60 m at a rate of 900 m^{3}/h. Assume the elevator is lifting wheat with a density of 770 kg/m^{3}.
solution
Start with the definition of power. Replace work with potential energy. We will ignore the kinetic energy of the wheat, since our real goal is to elevate the grain, not accelerate it. Replace mass with density times volume.
Rearrange it just a bit and substitute the numbers given to compute the power delivered as useful work.

P = 
(770 kg/m^{3}) 
(900 m^{3}) 
(9.8 m/s^{2})(60 m) 
(3,600 s) 


Compare this to the rated power of the motor to get the efficiency of the grain elevator.
η = 
W_{out} 
= 
P_{out} 
= 
113 kW 
= 75% 
W_{in} 
P_{in} 
150 kW 
practice problem 3
Write something different.
solution
practice problem 4
Write something completely different.
solution
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